We already saw how to calculate via Okumara-Hata model. By the way we can study for signal reception of Mobile Station which depends on the environmental place of Mobile Station.For this case we're discussing transmitting of Base Station Path loss (Downlink) Effective isotropic radiated power(EIRP)=55.35dB
- Case1: Prmin(MS)= -70dB
The signal reception of MS locates in the building (Indoor)
We get Path loss = EIRP - Prmin(MS) = 55.35 - (-70) = 125.35 dB
Logd = [125.35 - (69.55+26.16log900) + 13.82log26 + 0.016] / (44.9 - 6.55log26)= -0.0404
So Distance for Base Station transmitting d(BS) = 0.91km
- Case2: Prmin(MS)= -80dB
The signal reception of MS locates in car and room
We get Path loss = EIRP - Prmin(MS) = 55.35 - (-80) = 135.35 dB
Logd = [135.35 - (69.55+26.16log900) + 13.82log26 + 0.016] / (44.9 - 6.55log26) = 0.2402
So Distance for Base Station transmitting d(BS) = 1.73km
- Case3: Prmin(MS)= -90dB
The signal reception of MS locates outside the building (Outdoor)
We get Path loss = EIRP - Prmin(MS) = 55.35 - (-90) = 145.35 dB
Logd = [145.35 - (69.55+26.16log900) + 13.82log26 + 0.016] / (44.9 - 6.55log26) = 0.5208
So Distance for Base Station transmitting d(BS) = 3.31km
Summary:
Where:
K1: attenuation constant
K2: distance attenuation constant
K3, K4: MS antenna modifying factor
K5, K6: BTS antenna modifying factor
K7: diffraction modifying factor
Kclutter: attenuation correction value of the grounding objects
The values of K1 through K7 and Kclutter need to be manually set.
d: distance between the BTS and the MS (in km)
Hms: valid height of the MS antenna (in m)
Heff: valid height of the BTS antenna (in m)
+ Center of big city:
K1 = 69.55+26.16log(fc)-0.8 where fc:[150-1000] MHz
K1 = 46.30+Cm+(33.90+1.56)log(fc)-0.8 where fc:[1500-2000] MHz
+ Suburban area:
K1 = 69.55+(26.16+1.56log(fc))-0.8-2(log(fc/28))2-5.4 where fc:[150-1000] MHz
K1 = 46.30+(33.90+1.56log(fc))-0.8-2(log(fc/28))2-5.4 where fc:[1500-2000] MHz
+ Open area:
K1 = 69.55+(26.16+1.56log(fc))-0.8-4.78(log(fc/28))2-18.33log(fc)-40.94where fc:[150-1000] MHz
K1 = 46.30+(33.90+1.56log(fc))-0.8-4.78(log(fc/28))2-18.33log(fc)-40.94where fc:[1500-2000] MHz
Below table is K value
From above parameter we assume that
Coverage Calculation
All coverage calculation relate to cell site configuration: Omnidirectional Cell, 3 Sector or 6 Sector Cell and 2 Sector Cell.
In summary table we get d(BS) from calculation: 2.66Km.
- Omnidirectional Cell
A = 2.598 x d x d = 2.598 x 2.66 x 2.66 = 18.38 Km2
- 3 Sector or 6 Sector Cell
A = 1.949 x d x d = 1.949 x 2.66 x 2.66 = 13.79 Km2
- 2 Sector Cell
L = 2 x d = 2 x 2.66 = 5.32Km
We suppose one province that there are beautiful beach in our country:
-Population; 164779
-Number people per Km2: 179
-Surface area: 826Km2
If we observe population and tourism area, we choose3 Sector cell to implement in this area
Basic Number of Base Station = 826/13.79 = 59 BS
Note: Number of BSs depond on actual requirement of users in area so it can be less or more than theory calculation.
See also GSM Network Coverage I
- Case1: Prmin(MS)= -70dB
The signal reception of MS locates in the building (Indoor)
We get Path loss = EIRP - Prmin(MS) = 55.35 - (-70) = 125.35 dB
Logd = [125.35 - (69.55+26.16log900) + 13.82log26 + 0.016] / (44.9 - 6.55log26)= -0.0404
So Distance for Base Station transmitting d(BS) = 0.91km
- Case2: Prmin(MS)= -80dB
The signal reception of MS locates in car and room
We get Path loss = EIRP - Prmin(MS) = 55.35 - (-80) = 135.35 dB
Logd = [135.35 - (69.55+26.16log900) + 13.82log26 + 0.016] / (44.9 - 6.55log26) = 0.2402
So Distance for Base Station transmitting d(BS) = 1.73km
- Case3: Prmin(MS)= -90dB
The signal reception of MS locates outside the building (Outdoor)
We get Path loss = EIRP - Prmin(MS) = 55.35 - (-90) = 145.35 dB
Logd = [145.35 - (69.55+26.16log900) + 13.82log26 + 0.016] / (44.9 - 6.55log26) = 0.5208
So Distance for Base Station transmitting d(BS) = 3.31km
Summary:
We discuss other model ASSET Model\
ASSET Model is applied for 900MHz and 1800MHz in Macro BTS
Lp =K1+ K2logd + K3(hms) + K4loghms + K5log(Heff) + K6log(Heff)logd +K7 diffn + Kclutter Where:
K1: attenuation constant
K2: distance attenuation constant
K3, K4: MS antenna modifying factor
K5, K6: BTS antenna modifying factor
K7: diffraction modifying factor
Kclutter: attenuation correction value of the grounding objects
The values of K1 through K7 and Kclutter need to be manually set.
d: distance between the BTS and the MS (in km)
Hms: valid height of the MS antenna (in m)
Heff: valid height of the BTS antenna (in m)
+ Center of medium-size city:
K1 = 69.55+(26.16+1.56log(fc))-0.8 where fc:[150-1000] MHz
K1 = 46.30+(33.90+1.56)log(fc)-0.8 where fc:[1500-2000] MHz + Center of big city:
K1 = 69.55+26.16log(fc)-0.8 where fc:[150-1000] MHz
K1 = 46.30+Cm+(33.90+1.56)log(fc)-0.8 where fc:[1500-2000] MHz
+ Suburban area:
K1 = 69.55+(26.16+1.56log(fc))-0.8-2(log(fc/28))2-5.4 where fc:[150-1000] MHz
K1 = 46.30+(33.90+1.56log(fc))-0.8-2(log(fc/28))2-5.4 where fc:[1500-2000] MHz
+ Open area:
K1 = 69.55+(26.16+1.56log(fc))-0.8-4.78(log(fc/28))2-18.33log(fc)-40.94where fc:[150-1000] MHz
K1 = 46.30+(33.90+1.56log(fc))-0.8-4.78(log(fc/28))2-18.33log(fc)-40.94where fc:[1500-2000] MHz
Below table is K value
From above parameter we assume that
Coverage Calculation
All coverage calculation relate to cell site configuration: Omnidirectional Cell, 3 Sector or 6 Sector Cell and 2 Sector Cell.
In summary table we get d(BS) from calculation: 2.66Km.
- Omnidirectional Cell
A = 2.598 x d x d = 2.598 x 2.66 x 2.66 = 18.38 Km2
- 3 Sector or 6 Sector Cell
A = 1.949 x d x d = 1.949 x 2.66 x 2.66 = 13.79 Km2
- 2 Sector Cell
L = 2 x d = 2 x 2.66 = 5.32Km
We suppose one province that there are beautiful beach in our country:
-Population; 164779
-Number people per Km2: 179
-Surface area: 826Km2
If we observe population and tourism area, we choose3 Sector cell to implement in this area
Basic Number of Base Station = 826/13.79 = 59 BS
Note: Number of BSs depond on actual requirement of users in area so it can be less or more than theory calculation.
See also GSM Network Coverage I
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